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Enhanced destruction of Cu(CN)(3)(2-) by H2O2 under alkaline conditions in the presence of EDTA/pyrophosphate

机译:在EDTA /焦磷酸盐存在下在碱性条件下H2O2增强的对Cu(CN)(3)(2-)的破坏

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摘要

Oxidation of Cu(CN)(3)(2-) in water by H2O2 is less documented. The present study investigated the effects of pH, H2O2 dose and CN-/Cu(I) on oxidation of cu(CN)(3)(2-). Furthermore, oxidation of Cu(CN)(3)(2-) by H2O2 was investigated in the presence of ethylenediaminetetraacetate (EDTA) or pyrophosphate. The results indicated that Cu(CN)(3)(2-) oxidation was more favored at pH 9.5 and 11.0 than at pH 12.0. With the increase of H2O2 dose, rate of cu(cN)(3)(2-) oxidation was accelerated. Oxidation of Cu(CN)(3)(2-) was accelerated with CN-/Cu(I) decreasing from 4.0 to 2.8. In the presence of EDTA or pyrophosphate, oxidation of Cu(CN)(3)(2-) was significantly enhanced. 4.0 mM cyanide was nearly oxidized by 4.8 mM H2O2 in the presence of 1.0 mM EDTA. According to UV-Visible spectra variation of Cu(CN)(3)(2-) solutions, it was found that H2O2 firstly oxidized Cu(CN)(3)(2-) to Cu(CN)(2)(-). The successive oxidation of cyanide from Cu(CN)(2)(-) led to liberation of Cu(I). Cu(I) was oxidized into Cu(II) with formation of hydroxyl radicals (HO) or Cu(III). H2O2 was decomposed of into O-2 in the process. The strong bonding of Cu(II) to EDTA suppressed decomposition of H2O2 into O-2 and enhanced the effective utilization of H2O2 for cyanide destruction. By contrast, complexation of Cu(II) with pyrophosphate enhanced the catalytic redox reaction (Cu(I)/Cu(II) or Cu(I)/Cu(III)), improving cyanide oxidation. The results provide a possible way to improve treatment of Cu(CN)(3)(2-) wastewater by H2O2. (C) 2014 Elsevier B.V. All rights reserved.
机译:很少有证据表明H2O2在水中氧化Cu(CN)(3)(2-)。本研究调查了pH,H2O2剂量和CN- / Cu(I)对cu(CN)(3)(2-)氧化的影响。此外,研究了在乙二胺四乙酸盐(EDTA)或焦磷酸盐存在下H2O2对Cu(CN)(3)(2-)的氧化作用。结果表明,Cu(CN)(3)(2-)的氧化在pH 9.5和11.0时比在pH 12.0时更有利。随着H2O2剂量的增加,cu(cN)(3)(2-)的氧化速率加快。 Cu(CN)(3)(2-)的氧化加速,CN- / Cu(I)从4.0降至2.8。在EDTA或焦磷酸盐的存在下,Cu(CN)(3)(2-)的氧化显着增强。在1.0 mM EDTA存在下,4.0 mM氰化物几乎被4.8 mM H2O2氧化。根据Cu(CN)(3)(2-)溶液的紫外可见光谱变化,发现H2O2首先将Cu(CN)(3)(2-)氧化为Cu(CN)(2)(-) 。氰化物从Cu(CN)(2)(-)的连续氧化导致Cu(I)的释放。 Cu(I)被氧化成Cu(II),形成羟基(HO)或Cu(III)。在此过程中,H2O2分解为O-2。 Cu(II)与EDTA的牢固结合抑制了H2O2分解成O-2,并提高了H2O2对氰化物破坏的有效利用。相比之下,Cu(II)与焦磷酸盐的络合增强了催化氧化还原反应(Cu(I)/ Cu(II)或Cu(I)/ Cu(III)),从而改善了氰化物的氧化。该结果提供了一种可能的方法,以改善通过H2O2处理Cu(CN)(3)(2-)废水。 (C)2014 Elsevier B.V.保留所有权利。

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